From 1678bfd4fa5944538e6961d16be92db9b8fa4ed8 Mon Sep 17 00:00:00 2001
From: =?UTF-8?q?Andreas=20M=C3=BCller?= <andreas.mueller@ost.ch>
Date: Tue, 18 May 2021 12:45:59 +0200
Subject: add slides

---
 vorlesungen/slides/9/pf/primitiv.tex | 84 ++++++++++++++++++++++++++++++++++++
 1 file changed, 84 insertions(+)
 create mode 100644 vorlesungen/slides/9/pf/primitiv.tex

(limited to 'vorlesungen/slides/9/pf/primitiv.tex')

diff --git a/vorlesungen/slides/9/pf/primitiv.tex b/vorlesungen/slides/9/pf/primitiv.tex
new file mode 100644
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+++ b/vorlesungen/slides/9/pf/primitiv.tex
@@ -0,0 +1,84 @@
+%
+% primitiv.tex -- slide template
+%
+% (c) 2021 Prof Dr Andreas Müller, OST Ostschweizer Fachhochschule
+%
+\bgroup
+\begin{frame}[t]
+\setlength{\abovedisplayskip}{5pt}
+\setlength{\belowdisplayskip}{5pt}
+\frametitle{Primitive Matrix}
+\vspace{-20pt}
+\begin{columns}[t,onlytextwidth]
+\begin{column}{0.48\textwidth}
+\begin{block}{Definition}
+$A\ge 0$ heisst primitiv, wenn es ein $n>0$ gibt mit $A^n>0$
+\end{block}
+\uncover<9->{%
+\begin{block}{Intuition}
+\begin{itemize}
+\item<10->
+Markov-Ketten: $a_{ij} > 0$ bedeutet, $i$ von $j$ aus erreichbar.
+\item<11->
+Band: {\em alle} Verbindung mit allen Nachbarn
+\item<12->
+$n$-te Potenz: Pfade der Länge $n$ 
+\item<13->
+Durchmesser: wenn $n>\text{Durchmesser des Zustandsdiagramms}$,
+dann ist $A^n>0$
+\end{itemize}
+\end{block}
+}
+\end{column}
+\begin{column}{0.48\textwidth}
+\uncover<2->{%
+\begin{block}{Beispiel: Reduzible W'keitsmatrix}
+\vspace{-5pt}
+\begin{center}
+\begin{tikzpicture}[>=latex,thick]
+\fill[color=gray!40] (-1,0) rectangle (0,1);
+\fill[color=gray!40] (0,-1) rectangle (1,0);
+\draw[line width=0.3pt] (0,-1) -- (0,1);
+\draw[line width=0.3pt] (-1,0) -- (1,0);
+%\draw (-1,-1) rectangle (1,1);
+\node at (0,0) {$\left( \raisebox{0pt}[1cm][1cm]{\hspace*{2cm}} \right)$};
+\node at (-1.3,0) [left] {$\mathstrut W=$};
+\node at (0.5,0.5) {$0$};
+\node at (-0.5,-0.5) {$0$};
+\end{tikzpicture}
+\end{center}
+\vspace{-10pt}
+
+$\Rightarrow$ $W$ ist nicht primitiv
+\end{block}}
+\uncover<3->{%
+\begin{block}{Beispiel: Bandmatrix}
+\centering
+\begin{tikzpicture}[>=latex,thick]
+\begin{scope}
+\clip (-1,-1) rectangle (1,1);
+\foreach \n in {3,...,8}{
+	\pgfmathparse{0.3*(\n-2)}
+	\xdef\x{\pgfmathresult}
+	\only<\n>{
+		\fill[color=gray!40]
+			({-1.2-\x},1) -- (1,{-1.2-\x}) -- (1,{-0.8+\x})
+			-- ({-0.8+\x},1) -- cycle;
+	}
+}
+\fill[color=gray] (-1.2,1) -- (1,-1.2) -- (1,-0.8) -- (-0.8,1) -- cycle;
+\end{scope}
+\foreach \n in {2,...,8}{
+	\uncover<\n>{
+		\pgfmathparse{int(\n-2)}
+		\xdef\k{\pgfmathresult}
+		\node at (-1.3,0) [left] {$\mathstrut B^{\k}=$};
+	}
+}
+\node at (0,0) {$\left( \raisebox{0pt}[1cm][1cm]{\hspace*{2cm}} \right)$};
+\end{tikzpicture}
+\end{block}}
+\end{column}
+\end{columns}
+\end{frame}
+\egroup
-- 
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