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| author | Nao Pross <np@0hm.ch> | 2022-09-02 02:55:59 +0200 |
|---|---|---|
| committer | Nao Pross <np@0hm.ch> | 2022-09-02 02:55:59 +0200 |
| commit | 42b455abe1308e7ffd69f1d4ca6a44fd48969acf (patch) | |
| tree | f69673025e48af00c77fbd66f7644301250e9697 /buch/papers/kugel | |
| parent | kugel: Add references to other chapters (diff) | |
| download | SeminarSpezielleFunktionen-42b455abe1308e7ffd69f1d4ca6a44fd48969acf.tar.gz SeminarSpezielleFunktionen-42b455abe1308e7ffd69f1d4ca6a44fd48969acf.zip | |
kugel: Spelling
Diffstat (limited to '')
| -rw-r--r-- | buch/papers/kugel/applications.tex | 2 |
1 files changed, 1 insertions, 1 deletions
diff --git a/buch/papers/kugel/applications.tex b/buch/papers/kugel/applications.tex index f8f3edd..868d738 100644 --- a/buch/papers/kugel/applications.tex +++ b/buch/papers/kugel/applications.tex @@ -62,7 +62,7 @@ electric field is proportional to the charge density $\rho$. So, the Laplacian of the electric potential is proportional to the charge density! For those that are more familiar with the integral form of Maxwell's equation, we have also included an additional step using the divergence theorem, which brings us to the -electric Flux $\Phi$, which by Gauss' law (shown in the iconic\footnote{Every +electric flux $\Phi$, which by Gauss' law (shown in the iconic\footnote{Every electrical engineer has seen this picture so many times that is probably burnt in their eyes.} figure \ref{kugel:fig:eeg-flux}) equals the net electric charge. |