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authorNao Pross <np@0hm.ch>2022-08-29 01:32:55 +0200
committerNao Pross <np@0hm.ch>2022-08-29 01:32:55 +0200
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tree4400e95bfc914de231d562c34e9c7065e7842cec /buch/papers
parentkugel: Applications introductory paragraph (diff)
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kugel: EEG electrodynamics recap
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@@ -7,11 +7,59 @@ Fourier style expansion of any function on the surface of the sphere is very
useful in many fields of physics and engineering. Here we will present a few of
the most interesting applications we came across during our research.
-\subsection{Electroencephalography (EEG)}
+\subsection{Electroencephalography}
\begin{figure}
+ \centering
+ \subfigure[EEG Electrodes \label{kugel:fig:eeg-electrodes}]%
+ {\kugelplaceholderfig{.4\linewidth}{5cm}}
+ \qquad
+ \subfigure[Gauss' Law \label{kugel:fig:eeg-flux}]%
+ {\includegraphics[width=.4\linewidth]{papers/kugel/figures/flux}}
+ \caption{
+ \label{kugel:fig:eeg}
+ }
\end{figure}
+To start, we will look at an application that is from the field of medicine:
+electroencephalography. The \emph{electroencephalogram} (EEG) is a measurement
+of the electrical field on the scalp, which shows the brain's activity, and is
+used in many fields of research such as neurology and cognitive psychology. The
+measurement is done by wearing a cap that contains a number of evenly
+distributed electrodes, each of which measures the electric potential (voltage)
+at their location (figure \ref{kugel:fig:eeg-electrodes}). To see how this will
+relate to the spherical harmonics, we will first quickly recap a bit of physics,
+electrodynamics to be precise.
+
+In section \ref{kugel:sec:construction:eigenvalue} we have shown that the
+spherical harmonics arise from the surface spherical Laplacian operator, whose
+origin we did not consider too much, which is how mathematicians do their work.
+On the contrary, physicists usually do the opposite and start by discussing what
+is happening, since variables and functions represent physical quantities. So,
+we will quickly remind that the Laplacian operator does the following to an
+electric potential $\phi$:
+\begin{equation*}
+ \nabla^2 \phi
+ = \nabla \cdot \nabla \phi
+ = \nabla \cdot \mathbf{E}
+ = \rho / \varepsilon
+ \iff
+ \iiint_\Omega \nabla \cdot \mathbf{E} \, dv
+ = \iint_{\partial \Omega} \mathbf{E} \cdot d\mathbf{s}
+ = \Phi / \varepsilon.
+\end{equation*}
+Put into words: on the left we have the differential form, where we recall that
+the Laplacian (which is a second derivative) is the divergence of the gradient.
+Unpacking the notation we first see that we have the gradient of the potential,
+which is just the electric field $\mathbf{E}$, and then the divergence of said
+electric field is proportional to the charge density $\rho$. So, the Laplacian
+of the electric potential is the charge density! For those that are more
+familiar with the integral form of Maxwell's equation, we have also included an
+additional step using the divergence theorem, which brings us to the electric
+Flux, which by Gauss' law (shown in the iconic\footnote{Every electrical
+engineer has seen this picture so many times that is probably burnt in their
+eyes.} figure \ref{kugel:fig:eeg-flux}) is the net electric charge.
+
\subsection{Measuring Gravitational Fields}
\subsection{Quantisation of Angular Momentum}