From 4197abc20216c15f11660d63549eb8b765f1c892 Mon Sep 17 00:00:00 2001
From: =?UTF-8?q?Andreas=20M=C3=BCller?= <andreas.mueller@ost.ch>
Date: Wed, 25 May 2022 12:08:44 +0200
Subject: typos

---
 buch/chapters/060-integral/sqrat.tex | 6 +++---
 1 file changed, 3 insertions(+), 3 deletions(-)

(limited to 'buch/chapters/060-integral/sqrat.tex')

diff --git a/buch/chapters/060-integral/sqrat.tex b/buch/chapters/060-integral/sqrat.tex
index f6838e5..ceb8650 100644
--- a/buch/chapters/060-integral/sqrat.tex
+++ b/buch/chapters/060-integral/sqrat.tex
@@ -337,7 +337,7 @@ Durch Ableitung der Funktion
 \[
 F
 =
-\frac{1}{\sqrt{a}}\log\biggl(x+\frac{b}{2a}+\frac{y}{\sqrt{y}}\biggr)
+\frac{1}{\sqrt{a}}\log\biggl(x+\frac{b}{2a}+\frac{y}{\sqrt{a}}\biggr)
 \]
 kann man nachprüfen, dass $F$ eine Stammfunktion von $1/y$ ist,
 also
@@ -345,7 +345,7 @@ also
 \int
 \frac{1}{y}
 =
-\frac{1}{\sqrt{a}}\log\biggl(x+\frac{b}{2a}+\frac{y}{\sqrt{y}}\biggr).
+\frac{1}{\sqrt{a}}\log\biggl(x+\frac{b}{2a}+\frac{y}{\sqrt{a}}\biggr).
 \end{equation}
 
 %
@@ -458,7 +458,7 @@ Form
 =
 v_0 +
 C
-\log\biggl(x+\frac{b}{2a}+\frac{y}{\sqrt{y}}\biggr)
+\log\biggl(x+\frac{b}{2a}+\frac{y}{\sqrt{a}}\biggr)
 +
 \sum_{i=1}^n c_i
 \log v_i,
-- 
cgit v1.2.1

