From f144be56b0c7ec03f74c46928b1354a959a59246 Mon Sep 17 00:00:00 2001 From: =?UTF-8?q?Andreas=20M=C3=BCller?= Date: Sun, 22 May 2022 13:36:59 +0200 Subject: add hermite application presentation --- vorlesungen/slides/hermite/skalarprodukt.tex | 72 ++++++++++++++++++++++++++++ 1 file changed, 72 insertions(+) create mode 100644 vorlesungen/slides/hermite/skalarprodukt.tex (limited to 'vorlesungen/slides/hermite/skalarprodukt.tex') diff --git a/vorlesungen/slides/hermite/skalarprodukt.tex b/vorlesungen/slides/hermite/skalarprodukt.tex new file mode 100644 index 0000000..32b933f --- /dev/null +++ b/vorlesungen/slides/hermite/skalarprodukt.tex @@ -0,0 +1,72 @@ +% +% skalarprodukt.tex -- slide template +% +% (c) 2021 Prof Dr Andreas Müller, OST Ostschweizer Fachhochschule +% +\bgroup +\begin{frame}[t] +\setlength{\abovedisplayskip}{5pt} +\setlength{\belowdisplayskip}{5pt} +\frametitle{Skalarprodukt} +\vspace{-20pt} +\begin{columns}[t,onlytextwidth] +\begin{column}{0.48\textwidth} +\begin{block}{Orthogonale Zerlegung} +Orthogonale $H_k$ normalisieren: +\[ +\tilde{H}_k(x) = \frac{1}{\|H_k\|_w} H_k(x) +\] +mit Gewichtsfunktion $w(x)=e^{-x^2}$ +\end{block} +\begin{block}{``Hermite''-Analyse} +\begin{align*} +P(x) +&= +\sum_{k=1}^\infty a_k H_k(x) += +\sum_{k=1}^\infty \tilde{a}_k \tilde{H}_k(x) +\\ +\tilde{a}_k +&= +\| H_k\|_w\, a_k +\\ +a_k +&= +\frac{1}{\|H_k\|} +\langle \tilde{H}_k, P\rangle_w += +\frac{1}{\|H_k\|^2} +\langle H_k, P\rangle_w +\end{align*} +\end{block} +\end{column} +\begin{column}{0.48\textwidth} +\begin{block}{Integrationsproblem} +Bedingung: +\begin{align*} +a_0=0 +\qquad\Leftrightarrow\qquad +\langle H_0,P\rangle_w +&= +0 +\\ +\int_{-\infty}^\infty +P(t) w(t) \,dt += +\int_{-\infty}^\infty +P(t) e^{-t^2} \,dt +&= +0 +\end{align*} +\end{block} +\begin{theorem} +Das Integral von $P(t)e^{-t^2}$ ist in geschlossener Form darstellbar +genau dann, wenn +\[ +\int_{-\infty}^\infty P(t)e^{-t^2}\,dt = 0 +\] +\end{theorem} +\end{column} +\end{columns} +\end{frame} +\egroup -- cgit v1.2.1 From 83d215597b5df724022de2a08ae1dfa1e8d59497 Mon Sep 17 00:00:00 2001 From: =?UTF-8?q?Andreas=20M=C3=BCller?= Date: Thu, 2 Jun 2022 23:01:38 +0200 Subject: phases --- vorlesungen/slides/hermite/skalarprodukt.tex | 22 ++++++++++++++++------ 1 file changed, 16 insertions(+), 6 deletions(-) (limited to 'vorlesungen/slides/hermite/skalarprodukt.tex') diff --git a/vorlesungen/slides/hermite/skalarprodukt.tex b/vorlesungen/slides/hermite/skalarprodukt.tex index 32b933f..a51e9f6 100644 --- a/vorlesungen/slides/hermite/skalarprodukt.tex +++ b/vorlesungen/slides/hermite/skalarprodukt.tex @@ -18,6 +18,7 @@ Orthogonale $H_k$ normalisieren: \] mit Gewichtsfunktion $w(x)=e^{-x^2}$ \end{block} +\uncover<2->{% \begin{block}{``Hermite''-Analyse} \begin{align*} P(x) @@ -26,46 +27,55 @@ P(x) = \sum_{k=1}^\infty \tilde{a}_k \tilde{H}_k(x) \\ +\uncover<3->{ \tilde{a}_k &= \| H_k\|_w\, a_k +} \\ +\uncover<4->{ a_k &= \frac{1}{\|H_k\|} \langle \tilde{H}_k, P\rangle_w -= +}\uncover<5->{= \frac{1}{\|H_k\|^2} \langle H_k, P\rangle_w +} \end{align*} -\end{block} +\end{block}} \end{column} \begin{column}{0.48\textwidth} +\uncover<6->{% \begin{block}{Integrationsproblem} Bedingung: \begin{align*} a_0=0 +\uncover<7->{% \qquad\Leftrightarrow\qquad \langle H_0,P\rangle_w &= -0 +0} \\ +\uncover<8->{% \int_{-\infty}^\infty P(t) w(t) \,dt +}\uncover<9->{% = \int_{-\infty}^\infty P(t) e^{-t^2} \,dt &= -0 +0} \end{align*} -\end{block} +\end{block}} +\uncover<10->{% \begin{theorem} Das Integral von $P(t)e^{-t^2}$ ist in geschlossener Form darstellbar genau dann, wenn \[ \int_{-\infty}^\infty P(t)e^{-t^2}\,dt = 0 \] -\end{theorem} +\end{theorem}} \end{column} \end{columns} \end{frame} -- cgit v1.2.1