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author | Nao Pross <np@0hm.ch> | 2021-07-24 13:35:01 +0200 |
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committer | Nao Pross <np@0hm.ch> | 2021-07-24 13:36:32 +0200 |
commit | 1f8338006afdd62484f69b27a959c64c4774efa4 (patch) | |
tree | 0930abf17fd6f950735b0710f1612bce77dda502 /FuVar.tex | |
parent | Write on integration (diff) | |
download | FuVar-1f8338006afdd62484f69b27a959c64c4774efa4.tar.gz FuVar-1f8338006afdd62484f69b27a959c64c4774efa4.zip |
Small rewording and typo
Diffstat (limited to '')
-rw-r--r-- | FuVar.tex | 8 |
1 files changed, 4 insertions, 4 deletions
@@ -155,7 +155,7 @@ typesetting may trick you into thinking it is rigorous, but really, it is not. \(\vec{r}\) (with \(|\vec{r}| = 1\)) given by \[ \frac{\partial f}{\partial\vec{r}} - = \nabla\vec{r} f = \vec{r} \dotp \grad f + = \nabla_\vec{r} f = \vec{r} \dotp \grad f \] \end{definition} @@ -270,13 +270,13 @@ typesetting may trick you into thinking it is rigorous, but really, it is not. \end{remark} \begin{method}[Quickly find the eigenvalues of a \(2\times 2\) matrix] - Let + This is a nice trick. For a square matrix \(\mx{H}\), let \[ m = \frac{1}{2}\tr \mx{H} = \frac{a + d}{2} , - \qquad + \quad p = \det\mx{H} = ad - bc , \] - then \(\lambda = m \pm \sqrt{m^2 - p}\). + then \(\lambda_{1,2} = m \pm \sqrt{m^2 - p}\). \end{method} \begin{method}[Search for a constrained extremum in 2 dimensions] |