From 6a86853dc5965b5cd06537a2e05ba38980071051 Mon Sep 17 00:00:00 2001
From: Nao Pross <np@0hm.ch>
Date: Fri, 20 Aug 2021 09:20:33 +0200
Subject: Corrections

---
 tex/filters.tex | 6 +++---
 1 file changed, 3 insertions(+), 3 deletions(-)

(limited to 'tex/filters.tex')

diff --git a/tex/filters.tex b/tex/filters.tex
index f1ec820..913551c 100644
--- a/tex/filters.tex
+++ b/tex/filters.tex
@@ -94,13 +94,13 @@ To find the order of the filter given two parameters the formula is
 \[
   A(\Omega) = 10 \log\left(1 + e^2C_n^2(\Omega) \right),
 \]
-where \(C_n = \cos(n\arccos(\Omega))\) for \(|\Omega| \leq 1\) (in the passband), and when \(|\Omega| > 1\) (in the stopband) \(C_n = \cosh(n\arccosh(\Omega))\), is a so called Chebyshev polynomial of \(n\)-th order. \(e\) is a parameter, \emph{not the natural number (2.71\ldots)}. Chebyshev polynomials can be computed recursively with the formula
+where \(C_n = \cos(n\arccos(\Omega))\) for \(|\Omega| \leq 1\) (in the passband), and when \(|\Omega| > 1\) (in the stopband) \(C_n = \cosh(n\arccosh(\Omega))\), is a so called Chebyshev polynomial of \(n\)-th order. The ripple factor \(e\) is a parameter, \emph{not the natural number (2.71\ldots)}. Chebyshev polynomials can be computed recursively with the formula
 \[
   C_n = 2\Omega C_{n-1} - C_{n-2},
 \]
 and knowing that \(C_1 = \Omega\) and \(C_2 = 2\Omega^2 - 1\).
 
-The idea is that in the passband the attenuation is periodic and stays more or less constant, and in the stopband the function is no longer periodic and damps the frequencies. To find the parameter \(e\) given an \(A_\text{max}\)
+The idea is that in the passband the attenuation is periodic and stays more or less constant, and in the stopband the function is no longer periodic and damps the frequencies. To find the ripple factor \(e\) given an \(A_\text{max}\)
 \[
   e = \sqrt{10^{A_\text{max}/10} - 1},
 \]
@@ -115,7 +115,7 @@ and to find the order given two parameters
   } \right\rceil.
 \]
 
-\paragraph{Chebyshev II} Also known as \emph{inverse} Chebyshev. Let \(K(\Omega^2) = 1/e^2 C_n^2(1/\Omega)\).
+\paragraph{Chebyshev II} Also known as \emph{inverse} Chebyshev because \(K(\Omega^2) = 1/e^2 C_n^2(1/\Omega)\).
 
 \paragraph{Cauer}
 
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