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author | Nao Pross <np@0hm.ch> | 2021-12-22 18:14:32 +0100 |
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committer | Nao Pross <np@0hm.ch> | 2021-12-22 18:14:32 +0100 |
commit | cfb4d4236e4e64b8edd4041645ca48df4a090bc8 (patch) | |
tree | 58966bb49733a010bfc6b7d6d2ccd7e6b33a9e8f /doc/thesis | |
parent | Create makefile for slides (diff) | |
download | Fading-cfb4d4236e4e64b8edd4041645ca48df4a090bc8.tar.gz Fading-cfb4d4236e4e64b8edd4041645ca48df4a090bc8.zip |
Update slides and typo in theory
Diffstat (limited to 'doc/thesis')
-rw-r--r-- | doc/thesis/chapters/theory.tex | 2 |
1 files changed, 1 insertions, 1 deletions
diff --git a/doc/thesis/chapters/theory.tex b/doc/thesis/chapters/theory.tex index 87c5867..50759bb 100644 --- a/doc/thesis/chapters/theory.tex +++ b/doc/thesis/chapters/theory.tex @@ -261,7 +261,7 @@ Finally, the substitution \(l = m - n\) eliminates the sender's sample counter \ \end{equation} This result is very similar to the continuous time model described by \eqref{eqn:multipath-impulse-response} in the sense that each received digital sample is a sent sample convolved with a different discrete channel response (because of time variance). To see how the discrete CIR \begin{equation} \label{eqn:discrete-multipath-impulse-response} - h_l(m) = \sum_k c_k(mT) \sinc\left(l - \frac{\tau(mT)}{T}\right) + h_l(m) = \sum_k c_k(mT) \sinc\left(l - \frac{\tau_k(mT)}{T}\right) \end{equation} is different from \eqref{eqn:multipath-impulse-response} consider again the plot of \(h(\tau,t)\) in \figref{fig:multipath-impulse-response}. The plot of \(h_l(m)\) would have discrete axes with \(m\) replacing \(t\) and \(l\) instead of \(\tau\). Because of the finite bandwidth in the \(l\) axis instead of Dirac deltas there would be superposed sinc functions. |