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author | LordMcFungus <mceagle117@gmail.com> | 2021-03-22 18:05:11 +0100 |
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committer | GitHub <noreply@github.com> | 2021-03-22 18:05:11 +0100 |
commit | 76d2d77ddb2bed6b7c6b8ec56648d85da4103ab7 (patch) | |
tree | 11b2d41955ee4bfa0ae5873307c143f6b4d55d26 /vorlesungen/slides/2/cauchyschwarz.tex | |
parent | more chapter structure (diff) | |
parent | add title image (diff) | |
download | SeminarMatrizen-76d2d77ddb2bed6b7c6b8ec56648d85da4103ab7.tar.gz SeminarMatrizen-76d2d77ddb2bed6b7c6b8ec56648d85da4103ab7.zip |
Merge pull request #1 from AndreasFMueller/master
update
Diffstat (limited to 'vorlesungen/slides/2/cauchyschwarz.tex')
-rw-r--r-- | vorlesungen/slides/2/cauchyschwarz.tex | 94 |
1 files changed, 94 insertions, 0 deletions
diff --git a/vorlesungen/slides/2/cauchyschwarz.tex b/vorlesungen/slides/2/cauchyschwarz.tex new file mode 100644 index 0000000..a24ada8 --- /dev/null +++ b/vorlesungen/slides/2/cauchyschwarz.tex @@ -0,0 +1,94 @@ +% +% cauchyschwarz.tex +% +% (c) 2021 Prof Dr Andreas Müller, OST Ostschweizer Fachhochschule +% +\bgroup +\definecolor{darkgreen}{rgb}{0,0.5,0} +\begin{frame}[t] +\setlength{\abovedisplayskip}{5pt} +\setlength{\belowdisplayskip}{5pt} +\frametitle{Cauchy-Schwarz-Ungleichung} +\vspace{-15pt} +\begin{columns}[t,onlytextwidth] +\begin{column}{0.48\textwidth} +\begin{block}{Satz (Cauchy-Schwarz)} +$\langle\;,\;\rangle$ eine positiv definite, hermitesche Sesquilinearform +\[ +{\color{darkgreen} +|\operatorname{Re}\langle u,v\rangle| +\le +|\langle u,v\rangle| +\le +\|u\|_2\cdot \|v\|_2 +} +\] +Gleichheit genau dann, wenn $u$ und $v$ linear abhängig sind +\end{block} +\begin{block}{Dreiecksungleichung} +\vspace{-12pt} +\begin{align*} +\|u+v\|_2^2 +&= +\|u\|_2^2 + 2\operatorname{Re}\langle u,v\rangle + \|v\|_2^2 +\\ +&\le +\|u\|_2^2 + 2{\color{darkgreen}|\langle u,v\rangle|} + \|v\|_2^2 +\\ +&\le +\|u\|_2^2 + 2{\color{darkgreen}\|u\|_2\cdot \|v\|_2} + \|v\|_2^2 +\\ +&=(\|u\|_2 + \|v\|_2)^2 +\end{align*} +\end{block} +\end{column} +\begin{column}{0.48\textwidth} +\uncover<2->{% +\begin{proof}[Beweis] +Die quadratische Funktion +\begin{align*} +Q(t) +&= +\langle u+tv,u+tv\rangle \ge 0 +\\ +\uncover<3->{ +Q(t) +&= +\|u\|_2^2 + 2t\operatorname{Re}\langle u,v\rangle + t^2\|v\|_2^2} +\end{align*} +\uncover<4->{hat ihr Minimum bei}% +\begin{align*} +\uncover<5->{ +t&= +-\operatorname{Re}\langle u,v\rangle/\|v\|_2^2} +\intertext{\uncover<6->{mit Wert}} +\uncover<7->{ +Q(t) +&= +\|u\|_2^2 +-2\operatorname{Re}\langle u,v\rangle^2/\|v\|_2^2} +\\ +\uncover<7->{ +&\qquad + \operatorname{Re}\langle u,v\rangle^2/\|v\|_2^2} +\\ +\uncover<8->{ +0 +&\le +\|u\|_2^2-\operatorname{Re}\langle u,v\rangle^2/\|v\|_2^2} +\\ +\uncover<9->{ +\operatorname{Re}\langle u,v\rangle^2 +&\le +\|u\|_2^2\cdot\|v\|_2^2} +\\ +\uncover<10->{ +\operatorname{Re}\langle u,v\rangle +&\le +\|u\|_2\cdot\|v\|_2} +\qedhere +\end{align*} +\end{proof}} +\end{column} +\end{columns} +\end{frame} +\egroup |